## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 93

#### Answer

$(-\frac{1}{2},\frac{1}{2})$

#### Work Step by Step

We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Therefore, a line with endpoints $(\frac{1}{2},\frac{3}{8})$ and $(-\frac{3}{2},\frac{5}{8})$ will have a midpoint of $(\frac{\frac{1}{2}+(-\frac{3}{2})}{2},\frac{\frac{3}{8}+\frac{5}{8}}{2})=(\frac{-\frac{2}{2}}{2},\frac{\frac{8}{8}}{2})=(-\frac{1}{2},\frac{1}{2})$.

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