Answer
$(-\frac{1}{2},\frac{1}{2})$
Work Step by Step
We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$.
Therefore, a line with endpoints $(\frac{1}{2},\frac{3}{8})$ and $(-\frac{3}{2},\frac{5}{8})$ will have a midpoint of $(\frac{\frac{1}{2}+(-\frac{3}{2})}{2},\frac{\frac{3}{8}+\frac{5}{8}}{2})=(\frac{-\frac{2}{2}}{2},\frac{\frac{8}{8}}{2})=(-\frac{1}{2},\frac{1}{2})$.
