Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 39

Answer

$10x^{2}\sqrt x$

Work Step by Step

$\sqrt (100x^{5})=\sqrt (100x^{4}\times x)=\sqrt (100x^{4})\times\sqrt x=10x^{2}\sqrt x$ We know that $\sqrt (100x^{4})=10x^{2}$, because $(10x^{2})^{2}=(10\times10)\times x^{2+2}=100x^{4}$.
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