Intermediate Algebra (6th Edition)

The quotient rule holds that $\frac{\sqrt[n] a}{\sqrt[n] b}=\sqrt[n] (\frac{a}{b})$ (where $\sqrt[n] a$ and $\sqrt[n] b$ are real numbers and $\sqrt[n] b$ is nonzero). Therefore, $\frac{\sqrt[3] 24}{\sqrt[3] 3}=\sqrt[3] (\frac{24}{3})=\sqrt[3] 8=2$ We know this because $2^{3}=8$