Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 91

Answer

$(3,0)$

Work Step by Step

We know that the midpoint of the line segment whose endpoints are $(x_{1},y_{1})$ and $(x_{2},y_{2})$ is the point with coordinates $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$. Therefore, a line with endpoints (7, 3) and (-1, -3) will have a midpoint of $(\frac{7+(-1)}{2},\frac{3+(-3)}{2})=(\frac{6}{2},\frac{0}{2})=(3,0)$.
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