Answer
$4y^{3}$
Work Step by Step
$\sqrt [3] (64y^{9})=\sqrt [3] 64 \times\sqrt[3] (y^{9}))=4y^{3}$
We know that $\sqrt [3] 64=4$, because $4^{3}=64$. We also know that $\sqrt[3] (y^{9})=y^{3}$, because $(y^{3})^{3}=y^{3\times3}=y^{9}$
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 42
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
