Answer
TRUE
Work Step by Step
TRUE. The given expression follows the property of radicals that $\sqrt{a}\cdot\sqrt{b}=\sqrt{ab}$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set - Page 433: 112
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