## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 7 - Section 7.3 - Simplifying Radical Expressions - Exercise Set: 108

#### Answer

$4x^{2}+4x+1$

#### Work Step by Step

We are given the expression $(2x+1)^{2}$, which is equivalent to $(2x+1)(2x+1)$. We can use the FOIL method to simplify. F=$2x\times 2x=4x^{2}$ O= $2x\times1=2x$ I=$1\times 2x=2x$ L=$1\times1=1$ Now, we can add these terms together. $(2x+1)^{2}=(4x^{2})+(2x)+(2x)+(1)=4x^{2}+4x+1$

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