Answer
$v_d = 3.7\times 10^{-5}~m/s$
Work Step by Step
We can find the drift speed:
$v_d = \frac{i_e}{n_e~A}$
$v_d = \frac{i_e}{n_e~\pi~r^2}$
$v_d = \frac{1.0\times 10^{20}~/5.0~s}{(1.7\times 10^{29}~m^{-3})~(\pi)~(1.0\times 10^{-3}~m)^2}$
$v_d = 3.7\times 10^{-5}~m/s$