Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 27 - Current and Resistance - Exercises and Problems - Page 762: 27


(a) $R = 1.5~\Omega$ (b) $R = 3.5~\Omega$

Work Step by Step

(a) We can find the resistance: $R = \frac{\rho~L}{A}$ $R = \frac{\rho~L}{\pi~r^2}$ $R = \frac{(2.4\times 10^{-8}~\Omega~m)(2.0~m)}{(\pi)~(0.10\times 10^{-3}~m)^2}$ $R = 1.5~\Omega$ (b) We can find the resistance: $R = \frac{\rho~L}{A}$ $R = \frac{(3.5\times 10^{-5}~\Omega~m)(0.10~m)}{(1.0\times 10^{-3}~m)^2}$ $R = 3.5~\Omega$
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