Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)

Published by Pearson
ISBN 10: 0133942651
ISBN 13: 978-0-13394-265-1

Chapter 27 - Current and Resistance - Exercises and Problems - Page 762: 20


$E = 0.16~V/m$

Work Step by Step

We can find the required electric field strength: $E = \frac{I}{\sigma~A}$ $E = \frac{I}{\sigma~\pi~r^2}$ $E = \frac{5.0~A}{(1.0\times 10^7~S/m)~(\pi)~(1.0\times 10^{-3}~m)^2}$ $E = 0.16~V/m$
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