Answer
$E = 0.16~V/m$
Work Step by Step
We can find the required electric field strength:
$E = \frac{I}{\sigma~A}$
$E = \frac{I}{\sigma~\pi~r^2}$
$E = \frac{5.0~A}{(1.0\times 10^7~S/m)~(\pi)~(1.0\times 10^{-3}~m)^2}$
$E = 0.16~V/m$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 27 - Current and Resistance - Exercises and Problems - Page 762: 20
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