Answer
$Q = 0.13~C$
Work Step by Step
We can find the current:
$I = J~A$
$I = (7.5\times 10^5~A/m^2)(2.5\times 10^{-6}~m)(75\times 10^{-6}~m)$
$I = 1.4\times 10^{-4}~A$
We can find the charge that flows through the film in 15 minutes:
$Q = I~t$
$Q = (1.4\times 10^{-4}~A)(15\times 60~s)$
$Q = 0.13~C$
