Answer
$I = 1.8\times 10^{-8}~A$
Work Step by Step
We can find the average current:
$I = \frac{Q}{t}$
$I = \frac{9.0\times 10^{-12}~C}{0.50\times 10^{-3}~s}$
$I = 1.8\times 10^{-8}~A$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 27 - Current and Resistance - Exercises and Problems - Page 762: 13
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