Answer
$Q = 3.24\times 10^5~C$
Work Step by Step
We can find the charge that leaves the positive terminal:
$Q = I~t$
$Q = (90~A)(3600~s)$
$Q = 3.24\times 10^5~C$
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
by Knight, Randall D.
Published by
Pearson
ISBN 10:
0133942651
ISBN 13:
978-0-13394-265-1
Chapter 27 - Current and Resistance - Exercises and Problems - Page 762: 16
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