Answer
The wire is made of silver.
Work Step by Step
We can find the resistance:
$R = \frac{V}{I}$
$R = \frac{1.5~V}{8.0~A}$
$R = 0.1875~\Omega$
We can find the resistivity:
$R = \frac{\rho~L}{A}$
$\rho = \frac{R~A}{L}$
$\rho = \frac{R~\pi~r^2}{L}$
$\rho = \frac{(0.1875~\Omega)~(\pi)~(0.165\times 10^{-3}~m)^2}{1.0~m}$
$\rho = 1.6\times 10^{-8}~\Omega~m$
This value for the resistivity is closest to the resistivity of silver. Therefore, we can conclude that the wire is made of silver.
