Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 438: 39c

Answer

$$ \alpha=-124 \mathrm{rad} / \mathrm{s}^{2} $$ or $$|\alpha|=124 \mathrm{rad} / \mathrm{s}^{2}$$

Work Step by Step

(c) The angular acceleration is $$ \alpha=\frac{d^{2} \theta}{d t^{2}}=-\left(\frac{2 \pi}{T}\right)^{2} \theta_{m} \cos (2 \pi t / T)=-\left(\frac{2 \pi}{T}\right)^{2} \theta $$ When $\theta=\pi / 4$ , $$ \alpha=-\left(\frac{2 \pi}{0.500 \mathrm{s}}\right)^{2}\left(\frac{\pi}{4}\right)=-124 \mathrm{rad} / \mathrm{s}^{2} $$ or $|\alpha|=124 \mathrm{rad} / \mathrm{s}^{2}$
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