Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 438: 37b

Answer

$v = 0.56 \,\text{m/s}$

Work Step by Step

From the conservation law of energy, we get the velocity as next $$U + K = 0=\frac{1}{2} k y^{2}-m g y+\frac{1}{2} m v^{2}$$ Solve for $v$ we get it by \begin{align*} v&=\sqrt{2 g y-\frac{k}{m} y^{2}} \\ &= \sqrt{2 g y-\frac{g}{l} y^{2}}\\ &= \sqrt{2\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right)(0.08 \mathrm{m})-\left(\frac{9.8 \mathrm{m} / \mathrm{s}^{2}}{0.05 \mathrm{m}}\right)(0.08 \mathrm{m})^{2}}\\ &= 0.56 \,\text{m/s} \end{align*}
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