Answer
$9.42$ * $10^{-4}$ $J$
Work Step by Step
Given:
θ = 0.0800cos(4.43t + ϕ}
m = 60g = 0.06 Kg
L = 0.500 meters
Recognize that θ = 0.0800cos(4.43t + ϕ}, where 0.0800 is the max angular position, which I will refer to as $\theta$
We will use KE $\approx$ 0.5m$v^2$ (where v is the maximum velocity), with the equation v = L$\omega\theta$:
Substituting and solving:
KE $\approx$ 0.5m$(L\omega\theta)^2$ = 0.5(0.06)((0.500)(4.43)(0.0800)) = $9.42$ * $10^{-4}$ $J$
