Answer
The maximum speed of the particle is $~~4.0~m/s$
Work Step by Step
In part (a), we found that $\omega = 2.0 \times 10^3~rad/s$
We can find the maximum speed of the particle:
$v_{max} = A~\omega$
$v_{max} = (2.0 \times 10^{-3}~m)(2.0 \times 10^3~rad/s)$
$v_{max} = 4.0~m/s$
The maximum speed of the particle is $~~4.0~m/s$
