Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 438: 37a

Answer

$f=2.2Hz$

Work Step by Step

We can determine the frequency through the formula: $f=\frac{1}{2\pi}\sqrt\frac{g}{l}$ We plug in the known values in the formula to obtain: $f=\frac{1}{2\pi}\sqrt\frac{9.8}{0.050}$ $f=2.2Hz$
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