Answer
The distance from the pivot point to the center of mass of the pendulum is $~~47.7~cm$
Work Step by Step
Note that the center of mass of the disk is at the center of the disk.
The center of mass of the rod is at the center of the rod.
We can find the distance from the pivot point to the center of mass of the pendulum:
$d = \frac{(500~g)(L+r)+(270~g)(\frac{L}{2})}{500~g+270~g}$
$d = \frac{(500~g)(60.0~cm)+(270~g)(\frac{50.0~cm}{2})}{500~g+270~g}$
$d = 47.7~cm$
The distance from the pivot point to the center of mass of the pendulum is $~~47.7~cm$
