Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 15 - Oscillations - Problems - Page 438: 35c

Answer

The total mechanical energy is $~~0.080~J$

Work Step by Step

In part (b), we found that the maximum speed is $v_{max} = 4.0~m/s$ We can find the total mechanical energy: $E = K+U$ $E = K_{max}+0$ $E = \frac{1}{2}~m~v_{max}^2$ $E = (\frac{1}{2})~(0.010~kg)(4.0~m/s)^2$ $E = 0.080~J$ The total mechanical energy is $~~0.080~J$
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