Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 49

Answer

a) $Cu^{2+}$(aq) + $S^{2-}$(aq) -> $CuS$(s) b) $Co^{2+}$(aq) + $2OH^{-}$(aq) -> $Co(OH)_{2}$(s) c) $Ag^{+}$(aq) + $I^{-}$(aq) -> $AgI$(s)

Work Step by Step

a) Initially, the reaction is: $CuSO_{4}$(aq) + $Na_{2}S$(aq) -> $CuS$(s) + $Na_{2}SO_{4}$(aq) However, since $Na$ and $SO_{4}$ are spectator ions, it has to be removed. Therefore, the reaction turns out to be: $Cu^{2+}$(aq) + $S^{2-}$(aq) -> $CuS$(s) b) Initially, the reaction is: $CoCl_{2}$(aq) $2NaOH$(aq) -> $Co(OH)_{2}$(s) + $2NaCl$ (aq) However, since both $Na$ and $Cl$ are spectator ions, the reaction turns out to be: $Co^{2+}$(aq) + $2OH^{-}$(aq) -> $Co(OH)_{2}$(s) c) Initially, the reaction is: $AgNO_{3}$(aq) + $KI$(aq) -> $AgI$(s) + $KNO_{3}$(aq) However, since $K^{+}$ and $NO_{3}$$^{-}$ are spectator ions, the reaction turns out to be: $Ag^{+}$(aq) + $I^{-}$(aq) -> $AgI$(s)
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