Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 129: 54


a. $4.5∗10^{−3}$ mol $P_4O_6$ b. $3.2∗10^{−3}$ mol $Ca_3(PO_4)_2$ c. $7.0∗10^{−3}$ mol $Na_2HPO_4$$

Work Step by Step

a. $1.00\text{ grams $P_4O_6$}∗\frac{1 \text{ mol $P4O6$}}{219.89 \text{ grams $P_4O_6$}}=4.5∗10^{−3} \text{ mol $P_4O_6$}$ b. $1.00\text{ grams $Ca_3(PO_4)_2$}∗\frac{1 \text{ mol $Ca_3(PO_4)_2$}}{310.17 \text{ grams $Ca_3(PO_4)_2$}}=3.2∗10^{−3}\text{ mol $Ca_3(PO_4)_2$ }$ c. $1.00 \text{ grams $Na_2HPO_4$}∗\frac{1 \text{ mol $Na_2HPO_4$}}{141.96\text{ grams $Na2HPO4$}}=7.0∗10^{−3} \text{ mol $Na_2HPO_4$}$
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