# Chapter 3 - Stoichiometry - Exercises - Page 129: 59

a. $3.54*10^{22}\text{ molecules$NH_3$}$ b. $1.88*10^{22}\text{ molecules$N_2H_4$}$ c. $2.39*10^{21}\text{ molecules$(NH_4)_2Cr_2O_7$}$

#### Work Step by Step

a. $1.00\text{ grams$NH_3$}*\frac{1\text{ mol$NH_3$}}{17.031\text{ grams$NH_3$}}*\frac{6.0221*10^{23}\text{ molecules$NH_3$}}{1\text{ mol$NH_3$}}=3.54*10^{22}\text{ molecules$NH_3$}$ b. $1.00\text{ grams$N_2H_4$}*\frac{1\text{ mol$N_2H_4$}}{32.0452\text{ grams$N_2H_4$}}*\frac{6.0221*10^{23}\text{ molecules$N_2H_4$}}{1\text{ mol$N_2H_4$}}=1.88*10^{22}\text{ molecules$N_2H_4$}$ c. $1.00\text{ grams$(NH_4)_2Cr_2O_7$}*\frac{1\text{ mol$(NH_4)_2Cr_2O_7$}}{252.0649\text{ grams$(NH_4)_2Cr_2O_7$}}*\frac{6.0221*10^{23}\text{ molecules$(NH_4)_2Cr_2O_7$}}{1\text{ mol$(NH_4)_2Cr_2O_7$}}=2.39*10^{21}\text{ molecules$(NH_4)_2Cr_2O_7$}$

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