Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 63

Answer

$2.77*10^{19}\text{ molecules Freon-12}$ $3.26\text{ mg Cl}$

Work Step by Step

$0.00556\text{ grams Freon-12}*\frac{1\text{ mol Freon-12}}{120.9135\text{ grams Freon-12}}*\frac{6.0221*10^{23}\text{ molecules Freon-12}}{1\text{ mol Freon-12}}=2.77*10^{19}\text{ molecules Freon-12}$ $\frac{\text{ Mass of Cl}}{\text{ Molar Mass}}=\frac{70.906}{120.9135}*0.00556=3.26\text{ mg Cl}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.