Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 70

Answer

a. $180.157\text{ grams}$ b. $2.78*10^{-3}\text{ mol}$ $1.67*10^{21}\text{ molecules}$

Work Step by Step

a. $\text{ Molar Mass}=9*12.0107+8*1.00794+4*15.9994=180.157\text{ grams}$ b. $0.500\text{ grams}*\frac{1\text{ mol}}{180.157\text{ grams}}=2.78*10^{-3}\text{ mol}$ $0.500\text{ grams}*\frac{1\text{ mol}}{180.157\text{ grams}}*\frac{6.0221*10^{23}\text{ molecules}}{1\text{ mol}}=1.67*10^{21}\text{ molecules}$
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