Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 129: 65

Answer

a. $0.9292\text{ mol $Fe_2O_3$}$ b. $2.14*10^{-4}\text{ moles $NO_2$}$ c. $2.5*10^{-8}\text{ moles $BF_3$}$

Work Step by Step

a. $150.0\text{ grams $Fe_2O_3$}*\frac{1\text{ mol $Fe_2O_3$}}{159.6882\text{ grams $Fe_2O_3$}}=0.9292\text{ mol $Fe_2O_3$}$ b. $0.0100\text{ grams $NO_2$}*\frac{1\text{ mol $NO_2$}}{46.0055\text{ grams $NO_2$}}=2.14*10^{-4}\text{ moles $NO_2$}$ c. $1.5*10^{-6}\text{ molecules $BF_3$}*\frac{1\text{ mol $BF_3$}}{6.0221*10^{23}\text{ molecules $BF_3$}}=2.5*10^{-8}\text{ moles $BF_3$}$
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