Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 129: 69


a. $2.839*10^{-3}\text{ moles}$ b. $1.71*10^{21}\text{ molecules}$

Work Step by Step

a. $0.5000\text{ grams}*\frac{1\text{ mol}}{176.12412\text{ grams}}=2.839*10^{-3}\text{ moles}$ b. $0.5000\text{ grams}*\frac{1\text{ mol}}{176.12412\text{ grams}}*\frac{6.0221*10^{23}\text{ molecules}}{1\text{ mol}}=1.71*10^{21}\text{ molecules}$
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