Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 57

Answer

a. $70.0\text{ grams $N$}$ b. $140. \text{ grams $N$}$ c. $140.\text{ grams $N$}$

Work Step by Step

a. $5.00\text{ mols}*\frac{1\text{ mol $N$}}{1 \text{ mol $NH_3$}}*\frac{14.0067\text{ grams $N$}}{1\text{ mol $N$}}=70.0\text{ grams $N$}$ b. $5.00\text{ mols}*\frac{2 \text{ mol $N$}}{1 \text{ mol $N_2H_4$}}*\frac{14.0067\text{ grams $N$}}{1\text{ mol $N$}}=140. \text{ grams $N$}$ c. $5.00\text{ mols}*\frac{2\text{ mol $N$}}{1 \text{ mol $(NH_4)_2Cr_2O_7$}}*\frac{14.0067\text{ grams $N$}}{1\text{ mol $N$}}=140.\text{ grams $N$}$
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