Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 67

Answer

a.) 4.01 x $10^{22}$ atoms b.) 6.00 x $10^{22}$ atoms c.) 3.67 x $10^{22}$ atoms d.) 6.55 x $10^{22}$ atoms

Work Step by Step

a.) $\frac{5.00 g C_{2}H_{5}O_{2}N}{1}$$\times$$\frac{1 mol C_{2}H_{5}O_{2}N}{75.07 g C_{2}H_{5}O_{2}N}$$\times$$\frac{1 mol N}{1 mol C_{2}H_{5}O_{2}N}$$\times$$\frac{6.022 x 10^{23} atoms}{1 mol N}$ b.) $\frac{5.00 g Mg_{3}N_{2}}{1}$$\times$$\frac{1 mol Mg_{3}N_{2}}{100.95 g Mg_{3}N_{2}}$$\times$$\frac{2 mol N^{3+}}{1 mol Mg_{3}N_{2}}$$\times$$\frac{6.022 x 10^{23} atoms}{1 mol N^{3+}}$ c.) $\frac{5.00 g Ca(NO_{3})_{2}}{1}$$\times$$\frac{1 mol Ca(NO_{3})_{2}}{164.04 g Ca(NO_{3})_{2}}$$\times$$\frac{2 mol N^{5+}}{1 mol Ca(NO_{3})_{2}}$$\times$$\frac{6.022 x 10^{23} atoms}{1 mol N^{5+}}$ d.) $\frac{5.00 g N_{2}O_{4}}{1}$$\times$$\frac{1 mol N_{2}O_{4}}{91.98 g N_{2}O_{4}}$$\times$$\frac{2 mol N^{4+}}{1 mol N_{2}O_{4}}$$\times$$\frac{6.022 x 10^{23} atoms}{1 mol N^{4+}}$
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