## Chemistry 9th Edition

a. $137.992\text{ grams}$ b. $31.\text{ grams Al}$ c. $7.0*10^{23}\text{ molecules Al}$ d. $4.8*10^2\text{ grams Bauxite}$
a. Molar Mass = $2*26.981538+5*15.9994+4*1.00794=137.992\text{ grams}$ b. $0.58\text{ moles Bauxite}*\frac{137.992\text{ grams Bauxite}}{1\text{ moles Bauxite}}*\frac{53.963076\text{ grams Al}}{137.992\text{ grams Bauxite}}=31.\text{ grams Al}$ c. $0.58\text{ moles Bauxite}*\frac{2 \text{ moles Al}}{1\text{ moles Bauxite}}*\frac{6.0221*10^{23}\text{ molecules Al}}{1\text{ mol Al}}=7.0*10^{23}\text{ molecules Al}$ d. $2.1*10^4\text{ formula units Bauxite}*\frac{1 \text{ mole Bauxite}}{6.0221*10^{23}\text{ formula unitx Bauxite}}*\frac{137.992\text{ grams Bauxite}}{1 \text{ mole Bauxite}}=4.8*10^2\text{ grams Bauxite}$