Answer
0.0083 moles of carbon
0.10 g of carbon
Work Step by Step
Use stoichiometry, avagrado’s number (6.022 x 10^23 atoms/mol), and the average atomic mass of carbon to solve the problem
Chemistry 9th Edition
by Zumdahl, Steven S.; Zumdahl, Susan A.
Published by
Cengage Learning
ISBN 10:
1133611095
ISBN 13:
978-1-13361-109-7
Chapter 3 - Stoichiometry - Exercises - Page 128: 48
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