Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 128: 46


$5.392*10^{24} \text{ atoms Fe}$ $8.953 \text{ mol Fe}$

Work Step by Step

$500.0 \text{ grams Fe}*\frac{1\text{ mol Fe}}{55.845 \text{ grams Fe}}=8.953 \text{ mol Fe}$ $500.0 \text{ grams Fe}*\frac{1\text{ mol Fe}}{55.845 \text{ grams Fe}}*\frac{6.0221*10^{23} \text{ atoms Fe}}{1\text{ mol Fe}}=5.392*10^{24} \text{ atoms Fe}$
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