Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises - Page 128: 45


$4.64 \cdot 10^-20$ g Fe

Work Step by Step

(500 atoms)$(\dfrac{1 mol}{6.022 \cdot 10^{23}molecules})(\dfrac{55.85g}{1mol})$ = $4.64 \cdot 10^-20$ g Fe
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