Chemistry 9th Edition

Published by Cengage Learning
ISBN 10: 1133611095
ISBN 13: 978-1-13361-109-7

Chapter 3 - Stoichiometry - Exercises: 41

Answer

The abundance of $^{151}Eu$ is 48.013 %. The abundance of $^{153}Eu$ is 51.986 %.

Work Step by Step

We may relate the two abundances by $x$, the abundance of $^{151}Eu$ and $(1-x)$, the abundance of $^{153}Eu$. Therefore, we may write the following equation calculating the average atomic mass: $151.96=150.9196*x+152.9209(1-x)$ $151.96=-2.0013x+152.9209$ $x=\frac{152.9209-151.96}{2.0013}$ $x=0.48013$ $(1-x)=0.51986$
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