Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 8 - Section 8.4 - Plane Curves and Parametric Equations - 8.4 Exercises - Page 617: 4

Answer

a) So the graph will be linear (shown in picture) Arrows show direction which $t$ increasing b) $y=3t=3\times \dfrac {x+4}{6}=\dfrac {x+4}{2}=\dfrac {1}{2}x+2$

Work Step by Step

$x=6t-4\Rightarrow t=\dfrac {x+4}{6}$ $y=3t=3\times \dfrac {x+4}{6}=\dfrac {x+4}{2}=\dfrac {1}{2}x+2$ İf $ t\geq 0$ $\Rightarrow x\geq 6\times 0-4=-4$ a) So the graph will be linear (shown in picture) and when $x=-4$ then $y=0$ when $x=0$ then $y=2$ And graph will start with $x\geq -4$ Arrows show direction which $t$ increasing b) as we found previously $y=3t=3\times \dfrac {x+4}{6}=\dfrac {x+4}{2}=\dfrac {1}{2}x+2$
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