Answer
$x=4+t \\ y=-1+\dfrac{t}{2}$
Work Step by Step
The line passing through containing the point $P(p,q)$ with slope $m$ is expressed by the parametric equations as follows:
$x=p+t; y=q+mt$
Here, $t$ is any real number.
Now, the parametric equations for the given point are as follows:
$x=4+(1)t \\ y=-1+(\dfrac{1}{2}) t$
Thus, we have
$x=4+t \\ y=-1+\dfrac{t}{2}$
