Answer
(a) True.
(b) $(0,0)$, $(2,4)$.
(c) $y=x^2$, $path$. See graph.
Work Step by Step
(a) True. For $y=x^2$, we can write the parametric functions as $x=t+k,y=(t+k)^2$ where $k$ can be any real value.
(b) ... When t=0, the object is at $(0,0)$, and when t=1, the object is at $(2,4)$.
(c) ... we get the equation $y=x^2$, ... move along the same $path$ (can also use: parabola, curve, ...). See graph.
