Answer
$x=7+t$ and $y=8+t$
Work Step by Step
The line passing through containing the point $P(p,q)$ with slope $m$ is expressed by the parametric equations as follows:
$x=p+t; y=q+mt$
Here, $t$ is any real number.
Here, the slope $m=\dfrac{8-7}{7-6}=1$
Now, the parametric equations for the given point are as follows:
$x=7+t \\ y=8+(1)t$
Thus, we have
$x=7+t$ and $y=8+t$