Answer
$x=a~cos~t$
$y=b~sin~t$
Work Step by Step
$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$
$(\frac{x}{a})^2+(\frac{y}{b})^2=1$
$\frac{x}{a}=cos~t$
$x=a~cos~t$
$\frac{y}{b}=sin~t$
$y=b~sin~t$
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