Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Review - Exercises - Page 771: 68

Answer

Determinant: -10 Inverse Matrix (from left to right by row): $-0.3, -0,2$ (row 1) $-0.1, 0.2$ (row 2)

Work Step by Step

$\frac{1}{(2\times-3)-(2\times2)}$ $\frac{1}{-10}$ Swap the places of A and D, and put negatives in front of B and C. Multiply each by $\frac{1}{-10}$. Your answers are: $-0.3, -0,2, -0.1, 0.2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.