Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Review - Exercises - Page 771: 67

Answer

$|A|=1$ $\begin{array} \\A^{-1}=\\ \end{array} \begin{bmatrix} 9&-4\\ -2&1 \end{bmatrix}$

Work Step by Step

Step 1. List the matrix needed: $\begin{array} \\A=\\ \end{array} \begin{bmatrix} 1&4\\ 2&9 \end{bmatrix}$ Step 2. Calculate the determinant: $|A|=1\times9-4\times2=1$ Step 3. Calculate $A^{-1}$ (use the formula from section 10.5): $\begin{array} \\A^{-1}=\\ \end{array} \frac{1}{1\times9-4\times2}\begin{bmatrix} 9&-4\\ -2&1 \end{bmatrix} =\begin{bmatrix} 9&-4\\ -2&1 \end{bmatrix}$
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