Answer
No solution.
Work Step by Step
Step 1. List the matrices needed:
$\begin{array} \\A=\\ \end{array}
\begin{bmatrix} 2&1\\ 3&2 \end{bmatrix},
\begin{array} \\C=\\ \end{array}
\begin{bmatrix} 0&1&3\\ -2&4&0 \end{bmatrix} $
Step 2. Solve X from the equation: $X=\frac{1}{2}(5A-C)$
Step 3. Perform the operation:
$\begin{array} \\5A-C=\\ \end{array}
\begin{bmatrix} 10&5\\ 15&10 \end{bmatrix}-
\begin{bmatrix} 0&1&3\\ -2&4&0 \end{bmatrix} $
Step 4. Conclusion: because A and C are matrices of difference dimensions, there is no solution to the problem.
