Answer
From left to right by row,
$4,18$ (row 1)
$4,0$ (row 2)
$2,2$ (row 3)
Work Step by Step
For the indicated operation, each matrix is multiplied by a scalar. C by 2, and D by 3.
C with scalar applied:
$.5\times2=1$
$3\times2=6$
$2\times2=4$
$\frac{3}{2}\times2=3$
$-2\times2=-4$
$1\times2=2$
Now these values will be added to your matrix of D:
1+3=4
6+12=18
4+0=4
3+(-3)=0
-4+6=2
2+0=2
These answers are your new matrix. The sum of the two matrices.
