Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 10 - Review - Exercises - Page 771: 61

Answer

$\begin{bmatrix} -\frac{1}{3}&-1\\ -\frac{5}{3}&\frac{2}{3} \end{bmatrix}$

Work Step by Step

Step 1. List the matrices needed: $\begin{array} \\A=\\ \end{array} \begin{bmatrix} 2&1\\ 3&2 \end{bmatrix}, \begin{array} \\B=\\ \end{array} \begin{bmatrix} 1&-2\\ -2&4 \end{bmatrix} $ Step 2. Solve X from the equation: $X=\frac{1}{3}(B-A)$ Step 3. Perform the operation: $\begin{array} \\B-A=\\ \end{array} \begin{bmatrix} 1&-2\\ -2&4 \end{bmatrix}- \begin{bmatrix} 2&1\\ 3&2 \end{bmatrix} =\begin{bmatrix} -1&-3\\ -5&2 \end{bmatrix}, $ Step 4. Write the solution: $\begin{array} \\X=\frac{1}{3}(B-A)=\\ \end{array} \frac{1}{3}\begin{bmatrix} -1&-3\\ -5&2 \end{bmatrix} =\begin{bmatrix} -\frac{1}{3}&-1\\ -\frac{5}{3}&\frac{2}{3} \end{bmatrix}$
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