Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 9

$A= 40^\circ$ $a \approx3.23$ $b \approx3.55$

1. Find the third angle $A=180-95-45=40^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin40^\circ}=\frac{b}{sin45^\circ}=\frac{5}{sin95^\circ}$ 3. $a=\frac{5sin40^\circ}{sin95^\circ}\approx3.23$ 4. $b=\frac{5sin45^\circ}{sin95^\circ}\approx3.55$