Answer
$B=110^\circ$
$b\approx3.68$
$c\approx1.34$
Work Step by Step
1. Find the third angle $B=180-50-20=110^\circ$
2. Use the Law of Sines, we have $\frac{b}{sin110^\circ}=\frac{c}{sin20^\circ}=\frac{3}{sin50^\circ}$
3. $b=\frac{3sin110^\circ}{sin50^\circ}\approx3.68$
4. $c=\frac{3sin20^\circ}{sin50^\circ}\approx1.34$
