Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 21

$B =40^\circ$ $a \approx5.64$ $b \approx3.86$

1. Find the third angle $B=180-110-30=40^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin110^\circ}=\frac{b}{sin40^\circ}=\frac{3}{sin30^\circ}$ 3. $a=\frac{3sin110^\circ}{sin30^\circ}\approx5.64$ 4. $b=\frac{3sin40^\circ}{sin30^\circ}\approx3.86$