Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 16

$C=50^\circ$ $a\approx11.82$ $c\approx9.19$

1. Find the third angle $C=180-100-30=50^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin100^\circ}=\frac{c}{sin50^\circ}=\frac{6}{sin30^\circ}$ 3. $a=\frac{6sin100^\circ}{sin30^\circ}\approx11.82$ 4. $c=\frac{6sin50^\circ}{sin30^\circ}\approx9.19$