Chapter 7 - Applications of Trigonometric Functions - Section 7.2 The Law of Sines - 7.2 Assess Your Understanding - Page 551: 10

$C=95^\circ$ $a\approx2.84$ $b\approx2.58$

1. Find the third angle $C=180-40-45=95^\circ$ 2. Use the Law of Sines, we have $\frac{a}{sin45^\circ}=\frac{b}{sin40^\circ}=\frac{4}{sin95^\circ}$ 3. $a=\frac{4sin45^\circ}{sin95^\circ}\approx2.84$ 4. $b=\frac{4sin40^\circ}{sin95^\circ}\approx2.58$